Shock Absorbers / Preset Dampening (MAKC2530L)

Shock Absorbers / Preset Dampening MAKC2530L

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Product Details:

Manufacturer part number: MAKC2530L

Brand: MISUMI

Price: 80.60

Delivery time: 5 Days


Technical Data:

Stroke: 30 mm

Mounting Screw Nominal (M): M25

Max. Absorbed Energy: 88.2 J

Orifice Type: Tapered orifice

Main Body Material: [Steel] EN 1.0038 Equiv.


Part Number

Once your search is narrowed to one product,
the corresponding part number is displayed here.

MAKC2530L

Dimensional Drawing

MAKC
(Cap)

MAKS
(No Cap)

[ ! ] For parallel use of more than 2 pieces, be sure to use the same type and install them to receive the shock equally.
[ ! ] Operating ambient temperature: -5 to 70°C
[ ! ] Fully threaded if there is no h dimensions in the specification table.
[ ! ] Replace after 1,000,000 cycles.
[NG] Caps, nuts, etc., are not sold separately.
No.[M]Material (Main Body)[S] Surface Treatment
0404EN 1.4305 Equiv.
0604
0805EN CW614N Equiv.Electroless
Nickel Plating
1005Free Cutting Steel
1008
1210
1412
1612
2016
2022EN 1.0038 Equiv.
2530
2725
3035
CapPolyacetal
Only 2022 is urethane rubber.
·Caps, nuts, etc., are not sold separately.

Specification Table

Part Number
MAKC1008L
Part NumberThread Dia.
MXp
Stroke
S
Max. Absorbed Energy (E')Max. Equivalent
Mass
(me')
(kg)
Piston
Rod
Return Force
(N)
Max.
Drag Value
(N)
(L)(L1)L2dd1tB
(Wrench Flats)
Th
TypeNo.VelocityPer cycle
(J)
Per minute
(J)
MAKC
(Cap)


MAKS
(No Cap)
0404AM4
×
0.5
40.14.512.5 or less21432.6
(28.6)
20.14.531.248.1
(7)
20.5
B0.313.53
0604AM6
×
0.75
0.14.513 or less36333
(29)
20.54.61.89.2
(8)
2
B0.313.52
L0.522.53
0805AM8
×
0.75
50.3917.634.9 or less49037
(32)
22562512.7
(11)
21.5
B0.6822.55588
1005AM10
×
1.0
41.15.88 or less73539
(32)
3715
(13)
3
B0.988
1008A858.875.88 or less53
(46)
33
B1.4710
L2.94204.9 or less107855
(48)
34.55.5
M6
H2.5
1210AM12
×
1.0
101.9698159.8 or less147068
(60)
45583.5816.2
(14)
41.5
B2.4530
L6.8650196071
(63)
47.55.5
M14
H6
1412LM14
×
1.5
129.8176758.9 or less215678
(70)
52.51019.6
(17)
6
M20
H8
1612LM16
×
1.5
1214.72351109.8 or less294090
(75)
57.513.551521.9
(19)
M30
H13
2016LM20
×
1.5
1629.434323018.1 or less3528110
(93)
63141861727.7
(24)
8
M60
H25
2022LM20
×
1.5
2244.13927339.2 or less3920126.5
(112)
7614.5
M30
H15
2530LM25
×
1.5
3088.249039029.4 or less6370158
(140)
95152281837
(32)
10
M175
H75
2725LM27
×
1.5
257953942027.3 or less6370137.5
(117.5)
77.52320
M105
H47
3035LM30
×
1.5
351961176156047.1 or less14700190
(171.5)
116.520271018.541.6
(36)
14
M390
H173
[ ! ] L dimension values in ( ) are for MAKS.   kgf·m = J × 0.101972 kgf = N × 0.101972
* Each item in the specification table represents the following.
  • [Maximum Drag Value]The maximum value of the hydraulic resistance force that occurs during energy absorption (during stroke).
  • [Maximum Absorbed Energy]The maximum amount of energy that the absorber can receive at one time. (More than this will lead to damage)
  • [Equivalent Mass]The mass when the total energy to be absorbed by the absorber is equivalent to the kinetic energy in horizontal motion.
    It is "a value that converts selected factors such as thrust, the amount of collision material, and velocity into mass."
  • [Piston Return Force]This is the spring force that causes the piston to return from its pushed position.
Collision Velocity TypeCollision Velocity RangeMax. Operating CycleAllowable Angular Deviation
A
Low Speed B
L
0.3 to 1 m/s60 cycle/min*±2.5°
Medium Speed M
0.3 to 2 m/s
High Speed H
0.3 to 3 m/s
[ ! ] *No. 0404, 0604, and 0805 are 45 cycle/min; No. 3035 is 30 cycle/min.
[ ! ] When an eccentric angle adapter is used together, the allowable angular deviation will be ±10°.
Select an eccentric angle adapter with the same number as the shock absorber.
Part numbers without the same number are not compatible.

Selection Supporting Information

■Oil shock absorber is a shock absorber that
primarily uses oil. Compared with other cushioning materials (rubber, spring, air, etc.), they are compact and capable of repeatedly absorbing large impact energy
softly without rebound. Internal structure and basic principle of oil type shock absorbers are shown as follows.
When an object collides with a piston rod, the oil in the pressure chamber is compressed by a piston.
 The clearance between inner tube and piston is so small that compressed oil is forced out of the orifices.
 At this point, the impact energy is converted into heat energy by dynamic resistance.

The piston rod sinks into the shock absorber body so that the oil equal in volume to the piston
moves into the accumulator.
  This mechanism provides an ideal shock absorbing action.
Various absorption characteristics can be obtained depending on the number and size of orifices.
(Refer to classification according to absorption characteristics structures.)
Please note that when the wrong collision speed is selected, some abnormal reaction may occur during collision or the impact energy may not be absorbed in an ideal manner.
  
■Procedure of Selection
(1) Calculation of inertial energy (E1 ) 
According to examples of calculation for selection, calculate inertial energy based on collision mass (m), collision velocity (V)
·moment of inertia (I) and collision angular velocity (ω).

 

(2) Calculation of additional energy (E2') 
Confirm whether there is propulsion (F) or not and calculate the
additional energy according to Examples Of Calculation For Selection.

 

(3) Temporary decision of absorber stroke 
Obtain the temporary stroke (S') based on Fig. 1.

 

(4) Calculation of total energy 
Calculate the total energy from the sum of inertial energy (E1) and additional energy (E2 ').

 

(5) Select absorption characteristics structures from energy ratio 
Select an orifice type from Fig. 2 temporarily.

 

(6) Check max. absorbed energy per minute 
Calculate the energy (ET) per minute from the operating cycle (cycle/min) and total energy, and confirm whether or not the value is within the possible operating range.

 

(7) Check equivalent mass 
According to examples of calculation for selection, calculate the equivalent mass and confirm whether it is less than the max. equivalent mass in the catalog (me').
 

 

 

Calculate the temporary stroke S' with the Inertial Energy E1 (Adjustable / Fixed Force Type)

 

Fig. 2 Select the orifice type from energy ratio (additional energy E2' / inertial energy E1)
Examples of Calculation for Selection
Selection examples: Pure inertia collision (Horizontal collision without thrust)
Selection examples: Horizontal collision with air cylinder thrust force
Selection examples: Non-thrust stop when cylinder descends
App. Example
and
Collision Conditions

[Collision Conditions]
m = 25 kg
V = 0.6 m/s
F=ON
N = 30 times/min


Air Cylinder
Inner diameter ø40 Operating pressure 0.5 MPa

[Collision Conditions]
m = 30 kg
V = 0.6 m/s
N = 20 times/min

[Collision Conditions]
m = 15 kg
V = 0.2 m/s
N = 10 times/min

Air Cylinder
Inner diameter ø25 Operating pressure 0.5 MPa

Collision Velocity V
[m/s]
V = 0.6 m/sV = 0.6 m/s

V = 0.2 m/s

* Collision velocity V is actual measurements
or 1.5 to 2 times the average speed

Absorbed Energy

Moment of Inertia
Energy
E1

[J]
E1 = m × V22 = 25 × 0.622 = 4.5 JE1 = m × V2 2 = 30 × 0.62 2 = 5.4 JE1 = m × V2 2 = 15 × 0.22 2 = 0.3 J
Temporary stroke S'
[mm]
From Figure 1, S' = 20 mm (Select adjustable type)From Figure 1, S' = 15 mm (Select adjustable type)From Figure 1, S' = 10 mm (Select adjustable type)
Additional
Energy
E2
[J]
E2’ = 0JThrust of the cylinder is F = 628.4N
E2' = F × S' = 628.4 × 0.015 = 14.8 J
Cylinder thrust is F = 245.4 N
E2' = (F + mg) × S' = (245.4 + 15 × 9.8) × 0.01 = 3.92 J
Total energy E'
[J]
E’ = E1+E2’ = 4.5+0 = 4.5JE’ = E1+E2’ = 5.4+9.4 = 14.8JE’ = E1+E2’ = 0.3+3.92 = 4.22J
Equivalent Mass
me'
[kg]
me' = 2 × E' V2 = 2 × 4.5 0.62 = 25 kgme' = 2 × E' V2 = 2 × 14.8 0.62 = 82.2 kgme' = 2 × E' V2 = 2 × 4.22 0.22 = 211 kg
Tentative selection
Select Adjustable Type
Select L from the collision velocity.
Select MAC1612 from E and me'

(stroke
S = 12 mm)
Select Adjustable Type
Select medium speed M from the collision velocity.
Select MAC2016M from E and me'

(stroke
S = 16 mm)
Select Adjustable Type
Select ultra low speed S from Fig. 2.
Select MAC1612S from E and me'

(stroke
S = 12 mm)
Recalculation
E2 = 0J
E = E1+E2 = 4.5J
me = 2 × E V2 = 25 kgE2+F × S=10.1J
E = E1+E2 = 15.5J
me = 2 × E V2 = 86.1 kgE2 + (F + mg) × S = 4.71 J
E = E1+E2 = 0.3+4.71=5.01J
me = 2 × E V2 = 250 kg
Energy per minute ET
ET = E × N = 4.5 × 30 = 135 J/minET = E × N = 15.5 × 20 = 310 J/minET = E × N = 5.01 × 10 = 50.1 J/min
Confirmation
E, me, N, and ET are all OK
Select MAC1612L
E, me, N, and ET are all OK
Select MAC2016M
E, me, N, and ET are all OK
Select MAC1612S
* For pure-inertial collision without thrust force, select the orifice type by only collision velocity.
Examples of Calculation for Selection
Selection examples: Horizontal collision with belt conveyor thrust force
Selection examples: Collision with synchronous motor driven load
Selection examples: Horizontal rotation collision with torque
App. Example
and
Collision Conditions


Dynamic Friction Coefficient µ = 0.4

[Collision Conditions]
m = 5 kg
V = 0.5m/s
N = 20 times/min


Motor output P = 20 w,
Number of poles M = 36
Power Supply Frequency f = 50 Hz 
Reduction ratio K = 20

[Collision Conditions]
m = 1 kg
R=0.4 m
r = 0.3 m
θ=20°
N = 10 times/min
l = 43mr2
3 mr2 = 0.12 kg·m2
ω = 5.6 rad/s
F=59.3 N

[Collision Conditions]
I = 125.5 kg·m2
ω = 1.8 rad/s
R=1.25 m
N = 6 times/min
T=68.6 N⋅m

Collision Velocity V
[m/s]
V = 0.5m/sV = Rω = 0.40 × 5.6 = 2.24 m/sV = Rω = 1.25 × 1.8 = 2.25 m/s
Absorbed Energy
Moment of Inertia
Energy
E1
[J]
E1 = m × V22 = 5 × 0.522 = 0.625 JE1=22=0.12 × 5.622=1.88JE1=22=125.5 × 1.822=203.31J
Temporary stroke S'
[mm]
From Figure 1, S' = 5 mm (Select adjustable type)From Figure 1, S' = 10 mm (Select adjustable type)From Figure 1, S' = 50 mm (Select adjustable type)
Additional
Energy
E2
[J]
F = µmg = 0.4 × 5 × 9.8 = 19.6 N
E2’ = F·S’ = 19.6 × 0.005 = 0.098J
E2' = (F + mg) × S' = (59.3 + 1 × 9.8) × 0.01 = 0.69 JE2’=TR·S’=68.61.25 × 0.05=2.74J
Total energy E'
[J]
E’ = E1+E2’ = 0.625+0.098 = 0.723JE’ = E1+E2’ = 1.88+0.69 = 2.57JE’ = E1+E2’ = 203.31+2.74 = 206.05J
Equivalent Mass
me'
[kg]
me' = 2 × E'V2 = 2 × 0.723 0.52 = 5.8 kgme'= 2 × E'V2 = 2 × 2.57 2.242 = 1.0 kgme'= 2 × E'V2 = 2 × 206.05 2.252 = 81.4 kg
Tentative selection
Select Fixed Force Type
Select Single Orifice from V
Select MAKC1005 B from E' and me'

(stroke
S = 5 mm)
Select Adjustable Type
Select Multi-Orifice from Fig. 2.
Select MAC1210H from E' and me'

(stroke
S = 10 mm)
Select Adjustable Type
Select Speed H Type from Fig. 2.
Select MAC3650H from E' and me'

(stroke
S = 50 mm)
Recalculation
E2 = E2’ = 0.098J
E = E1+E2 = 0.723J
me = 2 × EV2 = 5.8 kgE2 = 0.69J
E = E1+E2 = 2.57J
me = 1.0 kgE2=TR·S=2.74J
E=E1+E2=206.05J
me = 2 × E V2 = 81.4 kg
Energy per minute ET
ET = E × N = 0.723 × 20 = 14.46 J/minET = E × N = 2.57 × 10 = 25.7 J/minET = E × N = 206.05 × 6 = 1,236.3 J/min
Confirmation
E, me, N, and ET are all OK
Select MAKC1005 B
E, me, N, and ET are all OK
Select MAC1210H
E, me, N, and ET are all OK
Select MAC3650H
■Shock Absorbers Classification according to absorption characteristics structures
Structure
Adjustable
Fixed Force Type
 
Tapered orifice
S Type
A Type
B Type
L Type
 There are three types of tapered orifices; a dashpot structure using a clearance between the piston and cylinder tube, a single-tube structure with an orifice in the piston, and a double-tube type tapered orifice, all of which exhibit similar drag force characteristics.
 
 
 The piston slides in a cylinder tube filled with oil, and a tapered orifice is installed in this piston.
Because the orifice area is constant over the entire stroke, as the shock absorption characteristics shown in the right graph, the resistance is the largest immediately after a collision but gradually reduces speed as the stroke continues.
 
 
Irregular Multi
Orifice
Medium Speed
Type M
 In this double-tube structure, the piston slides the
inner wall of the inner tube. This inner tube has several orifices along the
direction of strokes, and not constant damping, but
absorbs energy depending on various purposes. It is designed to absorb kinetic energy during the first half of stroke and
control speed during the second half. Therefore, it is well suited to
absorb energy against air cylinder thrust.
Multi
Orifice
High Speed
Type H
 In this double-tube structure, the piston slides in the
inner tube. This inner tube has several orifices along the direction
of strokes. Because the orifice area
becomes small gradually as the stroke speed slows down, the drag force fractures but the maximum drag is
lower.
[ ! ] Adjustable Type No.0806M is single orifice structure and No.3625 L Type is multi-orifice structure.
* When using shock absorbers (fixed force type) in parallel, calculate the total energy as shown below.
  E = E'/n
  E: Energy acting on each shock absorber
  E’: Total Energy
  n: Number of shock absorber receivers
* Do not use adjustable type shock absorbers in parallel.

App. Example

  • The shock absorber cannot be used at full stroke.
    If used at full stroke, there is a possibility of damage.
  • Install so that the object stops at a distance of 1 mm or more from the stroke end, or install an external stopper as required.
    Stopper nuts also can be used.

Cautions on Use

■ Precautions for Use
  • Shock absorbers use oil internally, and seals are used to prevent oil from leaking to the outside, but a perfect seal cannot be guaranteed.
    Because of this, it cannot be used in environments that prohibit oil.
  • Check for oil leaks and the return status of the piston rod. If leaking of a large amount of oil or failure of returning piston rod are found, there
    may be some abnormality and it should be replaced. If you use a defective product, it may cause damage to the unit to which it is installed.
  • With the number of uses, the energy absorption capacity will decrease due to the reduction in internal oil and wear of parts. Taking this into account, we recommend selecting a size that has at least 20 to 40% margin for the maximum absorbed energy.
  • The performance and functionality of shock absorbers may deteriorate depending on the load. Perform daily inspections to ensure that the required functions are met and to prevent accidents from occurring.

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Part Number
MAKC2530L
Part Number
Standard Unit Price
Minimum order quantityVolume Discount
Standard
Shipping Days
?
RoHSStroke
(mm)
Mounting Screw Nominal (M) Max. Absorbed Energy
(J)
Orifice Type Main Body Material Max. Collision Velocity
(m/s)
Overall Length
(mm)
Equivalent Mass
(kgf)
Max. Resisting Force Value
(N)
Piston Rod Return Force
(N)
Max. Operating Cycle
(cycle/min)
Max. Absorbed Energy (per Minute)
(J/min)
Cap Thread Size M

80.60 €

1 Available 5 Days 1030M2588.2Tapered orifice[Steel] EN 1.0038 Equiv.1158390637029.460490With CapM25X1.5

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  1. 1

Basic information

Main Body, Related Components Main Body Structure Fixed Type Usage Environment Standard
Min. Collision Velocity(m/s) 0.3 Operating Temperature Range(°C) -5::70

This page is Shock Absorbers / Preset Dampening, part number MAKC2530L.
You can find the detail information about specifications and dimensions on part number MAKC2530L.

Variation of this product

Part Number
MAKC0604B
MAKC0604L
MAKC0805A
MAKC2530M
MAKC2725H
MAKC2725L
Part NumberStandard Unit PriceMinimum order quantityVolume DiscountStandard
Shipping Days
?
RoHSStroke
(mm)
Mounting Screw Nominal (M) Max. Absorbed Energy
(J)
Orifice Type Main Body Material Max. Collision Velocity
(m/s)
Overall Length
(mm)
Equivalent Mass
(kgf)
Max. Resisting Force Value
(N)
Piston Rod Return Force
(N)
Max. Operating Cycle
(cycle/min)
Max. Absorbed Energy (per Minute)
(J/min)
Cap Thread Size M

44.08 €

1 Available 5 Days 104m60.3Tapered orificeEN 1.4305 Equiv.133236334513.5With CapM6X0.75

44.08 €

1 Available 5 Days 104m60.5Tapered orificeEN 1.4305 Equiv.133336334522.5With CapM6X0.75

24.56 €

1 Available 5 Days 105M80.39Tapered orificeEN CW614N Equiv.13734904.94517.6With CapM8X0.75

80.60 €

1 Available Same day

Stock

1030M2588.2Irregular Multi Orifice[Steel] EN 1.0038 Equiv.2158175637029.460490With CapM25X1.5

83.12 €

1 Available 5 Days 1025M2779Multi Orifice[Steel] EN 1.0038 Equiv.3137.547637027.360539With CapM27X1.5

83.12 €

1 Available 5 Days 1025M2779Tapered orifice[Steel] EN 1.0038 Equiv.1137.5420637027.360539With CapM27X1.5

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